From 5739f89e0d5241d70ea98c103e1ecf950ac5cf32 Mon Sep 17 00:00:00 2001
From: mitteneer <swebbguy@gmail.com>
Date: Sat, 28 Jun 2025 00:19:48 -0400
Subject: [PATCH] Write "friends" query

Will tell you which songs you listen to the most on the days you listen to some specified song
---
 src/queries.zig | 15 +++++++++++++++
 1 file changed, 15 insertions(+)

diff --git a/src/queries.zig b/src/queries.zig
index e298ea3..a665a58 100644
--- a/src/queries.zig
+++ b/src/queries.zig
@@ -457,3 +457,18 @@ pub fn loadQuery(entity: EntityType, query_type: QueryTypeEnum) GeneratedQuery {
         },
     };
 }
+
+// I'm pretty sure this query will tell you the number of days a song was played on the same day as a specified song
+// The output looked right at least. Can easily be changed into the number of times a song was played on the same day
+// as a specified song by removing DISTINCT from the first subquery (which would increase the count if a song was
+// played more than once in a day)
+
+//SELECT COUNT(albumsong), name
+//FROM (
+//  SELECT DISTINCT scrobbles.albumsong, songs.name, TO_CHAR(scrobbles.datetime, 'YYYY-MM-DD')
+//  FROM scrobbles
+//  INNER JOIN albumsongs ON albumsongs.id = scrobbles.albumsong
+//  INNER JOIN songs ON songs.id = albumsongs.song_id
+//  WHERE TO_CHAR(datetime,'YYYY-MM-DD') IN (
+//      SELECT DISTINCT TO_CHAR(datetime,'YYYY-MM-DD') FROM scrobbles WHERE albumsong = $1
+//)) GROUP BY albumsong, name ORDER BY COUNT(albumsong) DESC, name ASC;